Sum of digits of 1999^1999 Recursively reduced to 1 digit

Answer: 1

1999^1999 = A pretty big number, so calculating this and doing is not the way. 1999 = 1998 + 1 Now all numbers with (9k+1)^n = 9M+1 Therefore 1999^1999 = 9M+1 Sum of all digits of 9M recursively would be 9 9+1 = 10 on further reduction Sum = 1 Courtesy: Meenakshi :) 29 Jun, 2011
Comments (0)
You may also like
Popular Posts
Recent Posts
Tags
Random photo
Beach is this way Beach is this way in Havelock Island Andaman
On Facebook
Email Newsletter
Recent Comments
digitalpbk